NCERT Exemplar Solution for Class 10 Mathematics Chapter 13: Multiple Choice Questions

Here you will get the NCERT Exemplar Problems and Solutions for CBSE Class 10 Mathematics chapter 13, Statistics and Probability. This part contains solutions to Q. No. 12 to 26 of Exercise 13.1 of Class 10 Maths NCERT Exemplar Book.

Gurmeet Kaur
Mar 15, 2018, 12:46 IST
Class 10 Maths NCERT Exemplar Problems and Solutions
Class 10 Maths NCERT Exemplar Problems and Solutions

Here you get the NCERT Exemplar Problems and Solutions for CBSE Class 10 Mathematics chapter 13, Statistics and Prbability. This part includes solutions for questions 12 to 26 of exercise 13.1. All these are the Multiple Choice Questions framed from various important topics in the chapter. Each question is provided with a detailed yet simple step-wise explanation to help students learn the concept and logic working behind that particular question.

NCERT Exemplar problems are a very good resource for preparing the critical questions like Higher Order Thinking Skill (HOTS) questions. All these questions are very important to prepare for CBSE Class 10 Mathematics Board Examination 2017-2018 as well as for other competitive exams.

CBSE Class 10 Maths NCERT Exemplar Solution: Exercise 13.1 (Q. No. 1-11)

Few questions (Starting from Q. No. 12) from the Class 10 Maths NCERT Exemplar Exercise 13.1 are given below:

Question. 12   If an event cannot occur, then its probability is

(a) 1                        (b) 3/4                        (c) 1/2                (d) 0

Answer. (d)   

Explanation:

The event which cannot occur is called the impossible event with a probability equal to zero.

Question. 13   Which of the following cannot be the probability of an event?

(a) 1/3                     (b) 0.1                  (c) 3                       (d) 17/16

Answer. (d)                   

Explanation:

Probability of an event always lies between 0 and 1.

Question. 14   An event is very unlikely to happen. Its probability is closest to

(a) 0.0001               (b) 0.001               (c) 0.01                    (d) 0.1

Answer. (a)

Explanation:

The probability of an event which is very unlikely to happen is closest to zero and from the given options 0.0001 is closest to zero.

Question. 15   If the probability of an event is P, then the probability of its complementary event will be

(a) P – 1                      (b) P                  (c) 1 – P                  (d) 1 – 1/P

Answer. (c)   

Explanation:

Since, probability of an event + probability of its complementary event = 1.

∴ Probability of its complementary event = 1 – Probability of an event = 1 – P

Question. 16   The probability expressed as a percentage of a particular occurrence can never be

(a) less than 100                                        (b) less than 0

(c) greater than 1                                       (d) anything but a whole number

Answer. (b)

Explanation:

The probability expressed as a percentage always lies between 0 to 100. So, it cannot be less than 0.

Question. 17   lf P(A) denotes the probability of an event A, then

(a) P(A) < 0          (b) P(A) > 1        (c) 0 ≤ P(A) ≤ 1           (d) –1 ≤ P(A) ≤ 1

Answer. (c)   

Explanation:

The probability of an event always lies between 0 and 1.

Question. 18   If a card is selected from a deck of 52 cards, then the probability of its being a red face card is

(a) 3/26                    (b) 3/13                 (c) 2/13                    (d) 1/2

Answer. (a)   

Explanation:

In a deck of 52 cards, there are 12 face cards with 6 red and 6 black cards.

So, probability of getting a red face card = 6/52 = 3/26

Question. 19   The probability that a non-leap year selected at random will contain 53 Sundays is

(a) 1/7                           (b) 2/7                    (c) 3/7                    (d) 5/7

Answer. (a)

Explanation:

A non-leap year has 365 days with 52 weeks and 1 odd day. This 1 odd day may be any day of the week.

Thus, out of 7 days, there is 1 favourable event that this 1 day is Sunday.

Hence the probability of getting 53 Sundays = 1/7

To get the complete exercise visit the following link:

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